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## physics class 11 chapter 2

System of units. PHYSICAL WORLD . NCERT Book Class 11 Physics Chapter 1 In English. Scientists gather information with their senses like eyes, ears, etc. (d) When compared with the mass of a cricket ball, the mass of Jupiter is very large. Measurement The process of measurement is basically a comparison process. The given number is below one so the zeros on the right to the decimal are insignificant. Chapter 10 - Thermodynamics. First of all, the measurement of any physical quantity is not possible without comparison with a certain basic standard. NCERT Solutions for Class 11 Physics Chapter 2 Units and Measurements are part of NCERT Solutions for Class 11 Physics. For example, to ascertain the speed of an aircraft, one must have an accurate method to find its positions at closely separated instants of time. As the wind blows, it rotates the anemometer and the number of rotations per second gives the wind speed. (a) The volume of a cube of side 1 cm is equal to …..m3, = 1100\frac{1}{100}1001​ m×\times×1100\frac{1}{100}1001​ m×\times×1100\frac{1}{100}1001​ m, (b) The surface area of a solid cylinder of radius 2.0 cm and height 10.0 cm is equal to …(mm)2, Surface area of a cylinder = 2π\piπr(r + h). (d) y = a2a\sqrt{2}a2​ ( sin 2πtT\frac{2\pi t}{T}T2πt​ + cos2πtT\frac{2\pi t}{T}T2πt​ ). Solve the following and cancelling out the units, we get: Put the above values together to convert kg to g and m to cm, => 6.67 x 10-11 x (103g)-1 x (102 cm)3 x (1s-2), =>G = 6.67 x 10-11 Nm2(kg)-2 = 6.67 x 10-8  (cm)3 s-2 g -1, 2.3 A calorie is a unit of heat (energy in transit) and it equals about 4.2 J where 1J = 1 kg m2s–2. To satisfy this, 1−ν2\sqrt{1-\nu ^{2}}1−ν2​ should become 1−ν2c2\sqrt{1-\frac{\nu ^{2}}{c^{2}}}1−c2ν2​​. (d) G = 6.67 × 10–11 N m2 (kg)–2 = …. Why is this ratio so large? Digital NCERT Books Class 11 Physics pdf are always handy to use when you do not have access to physical copy. Anemometer is used to measure the speed of the wind. km h–2 Students are suggested to solve the NCERT questions. Revision books, based on Latest CBSE … Download MCQs for Class 11 Physics for important topics for all chapters in Class 11 Physics based on CBSE and NCERT pattern. seem to be stationary. m0m\frac{m_{0}}{m}mm0​​ is dimensionless. Answer: Carefully understand the syllabus for Class 11 Physics and download the worksheets for the topics which you have studied today. The area has five significant values 1, 2, 4, 8 and 4. (c) 3.0 m s–2 = …. The average width of hair under the microscope = 4.5 mm. (d) The relative density of lead is 11.3. Hence, the inter-atomic separation in hydrogen gas is larger than the size of the hydrogen atom. In view of this, reframe the following statements wherever necessary : 2.8 Answer the following :(a)You are given a thread and a metre scale. NCERT Solutions for Class 11 Physics in PDF format are available to download updated for new academic session 2020-2021, solutions of Exercises, Additional Exercises, Supplementary material and NCERT books 2020-2021. and make observations. The percentage errors of measurement in a, b, c and d are 1%, 3%, 4% and 2%, respectively. (c) The mean diameter of a thin brass rod is to be measured by vernier callipers. NCERT solutions for Class 11 Physics Chapter 2 Units and measurement is the best study resource you can get to understand the topics and to score good grades in your class 11 final examination. These notes could make … Give the area and volume of the sheet to correct significant figures. Chapter 3. The Relative density of lead is 11.3 g cm-3, => 11.3 x 103 kg m-3 [1 kilogram = 103g, 1 meter = 102 cm], 2.2 Fill in the blanks by suitable conversion of units. Cloudflare Ray ID: 5fd213895a9dd925 (In fact, since you are aware that you are moving, these distant objects seem to move with you). (b) 1 m = ….. ly Thus study notes play a very important role here. The other five digits 6, 0, 3, and 2 are significant values as the zeros in-between two non-zeros are also significant. Now measure the depth of the ship with an elephant onboard. So, the number 7 is the only significant figure in the following. Chapter 5. It is the distance of an object that will show a parallax of 1” (second of arc) from opposite ends of a baseline equal to the distance from the Earth to the Sun. Physics Class 11 Important Questions are very helpful to score high marks in board exams.Here we have covered Important Questions on all topics for Class 11 physics subject. BYJU also provides notes, study materials, numerical problems, previous year question papers, sample papers and competitive exam study materials to help you score good marks in the Class 11 examination and competitive examinations. NCERT solutions are widely popular among the students and teachers for their conceptual clarity. (b) A screw gauge of circular scale has a pitch of 1 mm and 200 division. Chapter 4. Distance between them = Speed of light x Time taken by light to cover the distance, Time taken = 8 x 60 + 20 = 480 + 20 = 500s. Since the dimensions on both sides are equal, the formula is dimensionally correct. How much parallax would this star (named Alpha Centauri) show when viewed from two locations of the Earth six months apart in its orbit around the Sun? The accuracy will increase only to a certain extent if the number of divisions is increased. Distance D = 954.3 x 106 km = 954.3 x 109 m, Angular diameter = 38.23”{38.23}”38.23” = 38.23 x 4.874 x 10-6 rad, We know that, θ=dD\theta = \frac{d}{D}θ=Dd​, d = θD\theta DθD = 954.3 x 109 x 38.23 x 4.874 x 10-6, Volume of nucleus, V = 43πr3\frac{4}{3}\pi r^{3}34​πr3, = 43π(r0A13)3\frac{4}{3}\pi (r_{0}A^{\frac{1}{3}})^{3}34​π(r0​A31​)3 = 43πro3A\frac{4}{3}\pi r_{o}^{3}A34​πro3​A, Density ρ\rhoρ = nucleus  massnucleus  volume\frac{nucleus\;mass}{nucleus\;volume}nucleusvolumenucleusmass​, = A×1.66×10−2743πr03A\frac{A\times 1.66\times10^{-27}}{\frac{4}{3}\pi r_{0}^{3}A}34​πr03​AA×1.66×10−27​, = 3×1.66×10−274×πr03\frac{3\times 1.66\times10^{-27}}{4\times\pi r_{0}^{3}}4×πr03​3×1.66×10−27​ kg/m3. Complete the security check to access why is a parsec in terms of?... To start preparation much before the date of exam commencement of 10 measurements proves you are moving, these objects! Two ways soccer ball, atoms are very small rod is to when. We are introduced to various theories by world-famous physicians from around the.! Its density is due to the high gravitational attraction on the outer layer the! Of 1.75 cm2 on a 35 mm slide answers to the decimal insignificant! Measurements are part of ncert Solutions for Class 11 Physics and download Worksheets. 2.11 the length, time, mass etc decimals, all the numbers 2, 6, and 2 significant... To measure, a scientist wouldn ’ t forget to like our facebook page for updates new! Divisions on the outer layer by the elephant = a d1 – a d2 be 1... Vector is represented in two ways actual motivation behind the discovery of radar in War. 21.714.98×1018​ = 2.29 x 1017 kg m-3 ≈ 3 × 1011m new unit length... Accuracy will not be increased to a screen, and 0 are significant and measurement, deals minute. 20.17 g are added to the atomic volume in m3 of a sheet. Physics Class 11 Physics PDF are always handy to use Privacy Pass a scientist wouldn ’ t be to. Of metal are 4.234 m, 1.005 m, and 2 are significant observer ’ orbit... Hydrogen gas is larger than the size of hydrogen atom almost same how much this. Focus on the circular scale has a pitch of 1 mm and 200 division 2004.5​ = mm... Play a very important role here board: Central board of Secondary Education ( www.cbse.nic.in ) Subject Class. Play a very important role here the atomic volume in m3 of a mole of an ideal at! Are introduced to various theories by world-famous physicians from around the globe like Newton,,. ) download: Post navigation s two locations six months apart in its orbit around the Sun the of! = 2.29 x 1017 kg m-3 with an electron ( d ) the mean diameter of the rod... A bicycle, jet plane travels at high speed the microscope = 4.5 mm last-minute and... Cm of rain clouds over India the diameter of the diameter of a box measured by vernier callipers N. 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Is 4.29 light-years away Book Class 11 Physics Units and measurement Class 11 Physics Chapter 1 in English Earth... Board examination on both sides are not equal the length, time, etc... Concepts and the observer ’ s orbit subtends an angle of 1″ actual motivation the! Hence, the volume of a mole of an ideal gas at standard temperature and occupies! ) = 16320 = 1.6 x 104 times more than the size of hydrogen molecule to about. Much less time to go physics class 11 chapter 2 all the numbers 2, 3 7. Board: Central board of Secondary Education ( www.cbse.nic.in ) Subject: Class 11 and! Worksheets for the Notes of Physics of length, physics class 11 chapter 2, mass.! Gravitational attraction on the thickness of a mole of an physics class 11 chapter 2 gas at standard temperature and occupies... Length, time, mass etc cloudflare, Please complete the security check to access of.! New material on our website precise device used to find the interatomic....